Question

What is the recursive rule for this geometric sequence?

2, 1/2, 1/8, 1/32

Answer your answers in the boxes

a =_•an-1

a1=_

Answer 1

Each new member of this sequence is 1/4 times the previous member. For example, 1/2 = (1/4)(2).

Thus, a(n+1) = (1/4)*a(n), with a(1)=2.

Answer 2

The given sequece is

`2 , 1/2, 1/8 , 1/32`

And we have to find the recursive formula of this geometric sequence.

First term is,

`a_(1) =2`

And the common ratio,

`r = (1/2)/(2) = (1)/(4)`

So the recursive formula is

`a_(n) = a_(n-1) * (1)/(4)`