Question

Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. XT =

Answer 1

I think its 3 sqrt of 2

Answer 2

`XT=3√(2)\ units`

Explanation:

see the attached figure to better understand the problem

we know that

Applying the Pythagoras Theorem

`XT^(2)= XY^(2)+YT^(2)`

In this problem we have

`XY=RS/2=6/2=3\ units`

`YT=XY=3\ units`

substitute

`XT^(2)= 3^(2)+3^(2)`

`XT^(2)= 18`

`XT=√(18)\ units`

Simplify

`XT=3√(2)\ units`