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Solve the differential equation: dy/dx = 4y2x1/3 A. - 1/y = 3x4/3 + C/y2 B. 1/y = 3x4/3 + C C. 1/y = 3x4/3 + C/y2 D. - 1/y = 3x4/3 + C

Solve the differential equation: dy/dx = 4y2x1/3 A. - 1/y = 3x4/3 + C/y2 B. 1/y = 3x4/3 + C C. 1/y = 3x4/3 + C/y2 D. - 1/y = 3x4/3 + C
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Solve the differential equation: dy/dx = 4y2x1/3

A. - 1/y = 3x4/3 + C/y2
B. 1/y = 3x4/3 + C
C. 1/y = 3x4/3 + C/y2
D. - 1/y = 3x4/3 + C

asked
User Sifatur Rahman
by
8.0k points

1 Answer

3 votes
The first thing you should do is use the method of variable separation. Then, integrate both sides to find the solution.
In this case the answer is
D. - 1/y = 3x4/3 + C
I attach the solution
Solve the differential equation: dy/dx = 4y2x1/3 A. - 1/y = 3x4/3 + C/y2 B. 1/y = 3x-example-1
answered
User GuruKay
by
7.7k points
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