Question

Find the roots of the polynomial equation. x^3-4x^2+x+26=0

Answer 1

The root of the polynomial is equal to
`x=-2`

Explanation:

we have

`x^(3)-4x^(2) +x+26=0`

we know that

The roots of the polynomial are the values of x when the value of the polynomial is equal to zero ( x-intercepts)

Using a graphing tool

see the attached figure

The polynomial has only one x-intercept

For
`x=-2` -----> the value of the polynomial is equal to zero

therefore

The root of the polynomial is equal to
`x=-2`