Question

6, -12, 24, 8th term of geometric sequence

Answer 1

a₈ = - 768

Explanation:

The nth term of a geometric sequence is

`a_(n)` = a₁
`(r)^(n-1)`

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r =
`(a_(2) )/(a_(1) )` =
`(-12)/(6)` = - 2 , then

a₈ = 6 ×
`-2)^(7)` = - 6 × - 128 = - 768