Given f(x)= 2^x +1 
 
 g(x)= -x +4 
 
We have to find the value of x which satisfy the condetion : f(x)= g(x) 
 
 
Solution : let us place expression given for f(x) and g(x) equal to each other 
 
 This gives us : 2^x + 1 = -x+ 4 
 
 Let us bring all x terms on left side only 
 
 we add x on both sides this makes : 2^x +1 +x = -x+ 4 +x 
 
 on the right side -x and +x becomes a "0" 
 
 we get : 2^x + 1 + x = 4 
 
 
 * let us nopw bring all the numeric terms on left side only 
 subtract 1 from both sides : 2^x + 1 + x - 1 = 4- 1 
 
 on the left side +1 and -1 becomes a "0" 
 on the rigth side 4-1 becomes a "3" 
 
 equation look like : 2^x + x = 3 
 
 We can see the right side is an odd number 
 on the left side there is sum of two terms one of them is 2^x which is an even number always . 
 
 we know that sum of an even number with an even number result out an even number 
 but we want a result as an odd number (3) 
 
 this suggest that x should be an odd number . 
 Also the sum of 2^x and x is 3 so 2^x should be smaller than 3 
 
 the smallest value ( x being an integer ) 
 2^x can have is : 2^1= 2 which is for x=1 
 
 let us check plugging x= 1 . 2^1 + 1 = 3 which is TRUE 
 
 Hence answer is x= 1