Question

analyze the results of a cross between two organisms that are both heterozygous for two different genes (AaBb) use a punnett square to evaluate the possible genotypes list all the genotypes form you punnett square in answer space determine how many phenotypes can be produced in the offspring determine the probability of producing offspring with the aabb genotype

Answer 1

The cross of heterozygous AaBb as parental phenotype led to formation of 16 phenotype of the offspring.This is because this is dihybrid form of inheritance .The probability of having aabb offspring is 1/16 since there is only one aabb type of offspring phenotype out of the 16. An illustration of how crossing is done is as per punnet square below