A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees. Find the area of the triangle.

Question

asked Jan 25, 2019 38.5k views

2 Answers

Icastell · Answer 1 · 2019-01-29T21:58:00+0000

Answer:

The area of the triangle is 61.2 sq. cm.

Explanation:

Given : A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees.

To find : The area of the triangle?

Solution :

The area of triangle when two sides and one angle between them is given is

$A=(1)/(2)* a* b* \sin\theta$

Where, a and b are the sides of the triangle

a=10 cm and b=16 cm

$\theta=130^\circ$ is the angle between two sides

Substituting the values in the formula,

$A=(1)/(2)* 10* 16* \sin 130$

A=80* 0.766

A=61.28cm^2

Therefore, The area of the triangle is 61.2 sq. cm.