Question

Find the zeros : x(x^2+13x+40)

Answer 1

Given Expression

`\rm \hookrightarrow \: x ( \: x^2+13x+40)`

Can Be Written As

`\rm \hookrightarrow \: {x}^(2) + 13x + 40`

Now,

`\rm \hookrightarrow \: {x}^(2) + 5x + 8x+ 40`

`\rm \hookrightarrow \: {x}(x +5) + 8(8x + 5)`

Answer 2

the zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.