Question

Carmen enters a painting in an art contest. The contest rules say that all paintings must be rectangular, with an area no greater that 3,003.04 cm2. Carmen painting is 16 cm wode. What is the greatest lenth the painting can have and still have an area within the contest rules?

Answer 1

187.69 cm

Explanation:

We have that the maximum area allowed for the painting = 3003.04
`cm^(2)`.

Also, the width of Carmen's painting = 16 cm.

It is required to maximum length of Carmen's painting that will be eligible to take part in the competition.

Let the maximum length of the painting = L cm.

Since, Area of a rectangle = length of the rectangle × width of the rectangle.

i.e. 3003.04 = L × 16

i.e.
`L=(3003.04)/(16)`

i.e. L = 187.69 cm

Hence, the length of the painting should not exceed 187.69 cm in order to be eligible to participate in the competition.