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4 votes
Given: ∆AKL, AK = 9 m∠K = 90° m∠A = 60° Find: P∆AKL The area of ∆AKL

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User Vanguard
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1 Answer

4 votes

Answer:


Explanation:


Given: ∆AKL, AK = 9 m∠K = 90° m∠A = 60° Find: P∆AKL The area of ∆AKL-example-1
answered
User Neil Miller
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8.3k points
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