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Here are the first four terms of a sequence. 1/2 4/3 9/4 16/5. find the nth term of this sequence.

asked
User Rranjik
by
7.9k points

2 Answers

2 votes

Answer:n^2/(n+1)


Explanation:

n=1

1^2/(1+1) = 1/2

n=2

2^2/(2+1) = 4/3

n=3

3^2/(3+1) = 9/4

answered
User Revo
by
9.3k points
0 votes

Answer:

n^2/(n + 1)

Explanation:

The numerators are the squares of the sequence numbers 1^1 2^2 3^2....

The denominators are the sequence numbers + 1, so the nth term is

n^2/(n + 1).

answered
User Hans Roelofsen
by
7.6k points

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