Question

Use the dot product to find |v| when v=(-8,2)

Answer 1

2√17

Explanation:

V = (-8, 2)

|v| = √((-8)^2 + 2^2)

= √(64 + 4)

= √68

= √4* √17

= 2√17

Answer 2

= 2 sqrt(17)

Explanation:

To find the magnitude of v using the dot product

|v| = sqrt(v1*v1 + v2*v2)

= sqrt( -8*-8 + 2*2)

= sqrt(64+ 4)

= sqrt(68)

= sqrt(4*17)

= sqrt(4) sqrt(17)

= 2 sqrt(17)