Question

A runner goes 88 m in 9.2 seconds what was his acceleration

Answer 1

2.1m/s²

Step-by-step explanation:

Given parameters:

Distance = 88m

Time taken = 9.2s

Unknown:

Acceleration = ?

Solution:

To solve this problem, we use the kinematics equation below;

S = ut +
`(1)/(2)` at²

S is the distance

u is the initial velocity = 0m/s

t is the time

a is the acceleration

88 = (0 x 9.2) +
`(1)/(2)` x a x 9.2²

88 = 42.32a

a = 2.1m/s²