Answer: 2x^3 - 7x^2 + 6x - 9 which is choice D
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Work Shown:
One way is to use the distribution rule two times
(x-3)(2x^2-x+3) = y(2x^2-x+3) ........... replace (x-3) with y
(x-3)(2x^2-x+3) = y(2x^2)+y(-x)+y(3) .... distribution rule
(x-3)(2x^2-x+3) = 2x^2*(y) - x(y) + 3(y)
(x-3)(2x^2-x+3) = 2x^2*(x-3) - x(x-3) + 3(x-3) .... replace y with x-3
(x-3)(2x^2-x+3) = 2x^3-6x^2 - x^2 + 3x + 3x - 9 ... distribution rule
(x-3)(2x^2-x+3) = 2x^3 - 7x^2 + 6x - 9
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Or we can use the box method (see the attached image below). This is a visual way to organize the terms. You'll probably notice that the box method is basically the distribution rule. Each row is one distribution being applied. In row 1, we have x distributed to (2x^2-x+3). In row 2, we have -3 distributed to (2x^2-x+3). I color coded the table cells to highlight the like terms. Those like terms combine to -6x^2-x^2 = -7x^2 and 3x+3x = 6x as shown in the steps for the distribution above.
Each interior cell in the box is found by multiplying the corresponding outer terms. For example, in the first row, first column we have x^3 which is the result of multiplying the outer x and x^2 terms.