Question

5. Grayson a green number cube and a white number cube. the faces of the cubes are number 1 through 6. Graysen roll each cube one time. What is the probability that the green cube will land with an even number face up and the white cube will land with a number greater than 2 face up?

A.1/9
B.1/36
C.1/3
D.1/6

Answer 1

To find the probability of the green cube landing with an even number face up and the white cube landing with a number greater than 2 face up, multiply the probabilities of each event happening. The probability is 1/3.

Step-by-step explanation:

To find the probability that the green cube will land with an even number face up and the white cube will land with a number greater than 2 face up, we need to determine the number of favorable outcomes and the total number of possible outcomes.

The green cube has 3 even numbers (2, 4, and 6) out of 6 faces, so the probability of the green cube landing with an even number face up is 3/6 or 1/2.

The white cube has 4 numbers greater than 2 (3, 4, 5, and 6) out of 6 faces, so the probability of the white cube landing with a number greater than 2 face up is 4/6 or 2/3.

To find the probability of both events happening, we multiply the probabilities: (1/2) * (2/3) = 1/3.

Therefore, the probability that the green cube will land with an even number face up and the white cube will land with a number greater than 2 face up is 1/3. Option C, 1/3, is the correct answer.

Answer 2

Answer: P(G even and W>2) = 1/3 or 0.333 or 33.3%

Step-by-step explanation:

Independent events multiply probabilities,

P(G even)=1/2, P(W>2)=2/3, P(G even and W>2)= 1/2 × 2/3 = 1/3.

Without using definition of "independent events", or rules referring to them, I use sample space S of 36 points, and P(event) = #(event)/#(sample space).

Points are labeled with two digits, left is green die, right is white die. S = {11,12,13,14,15,16,21,...26,...,61,...,66}, and #(S)=36.

An event E is a subset of S, and

0 <= #(E) <= #(S) = 36.

Event G even is GE={21,22,23...,41,42,...,61,...,66},

#(G even)=18

Event "W>2" = W2 ={13,14,15,16,23,24...,63,64,65,66},

#(W>2)=24.

Event G even and W>2 GEW2={23,24,25,26,43,44,45,46,63,64,65,66),

#(GEW2)=12

P(GEW2)=#(GEW2)/#(S)=12/36=1/3=33.3%