Question

The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation equals=4t squared 4t2. suppose that a basketball player has a vertical leap of 44 feet 1111 inches. find the hang time for this leap.

Answer 1

Answer: 1.1 seconds

Explanation:

leap = 4t² ; leap = 4 ft 11 inches, find t

`4(11)/(12) = 4t^2`

`(59)/(12) = 4t^2`

`(59)/(48) = t^2`

`\sqrt{(59)/(12)} = √(t^2)`

`√(1.23) = t`

1.1 = t