Question

5x^2-(3xy-7x^2)+(5xy-12x^2)
When x=-0.25, and y=4

Answer 1

-2

Explanation:

5x^2-(3xy-7x^2)+(5xy-12x^2)

5x^2-3xy+7x^2+5xy-12x^2

[(5x^2+7x^2-12x^2)=0]

-3xy+5xy= -3(-.25)(4)+5(-.25)(4)

-3(-.25)(4)+5(-.25)(4)= 3-5= -2

-2

Answer 2

`5x^2-(3xy-7x^2)+(5xy-12x^2)=5x^2-3xy+7x^2+5xy-12x^2=2xy\\\\ 2\cdot(-0.25)\cdot4=-2`