Question

Compute the following 8c8

Answer 1

1

Explanation:

using the definition of n
`C_(r)`

=
`(n!)/(r!(n-r)!)`

where n! = n(n - 1)(n - 2)........ × 3 × 2 × 1

note that 0! = 1

8
`C_(8)` =
`(8!)/(8!(0!))`= 1 ← cancel 8!