Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n) = 5 + (n-1)(1/6)

Answer 1

`A(n)=5+(n-1)\left((1)/(6)\right)=5+(1)/(6)n-(1)/(6)=(1)/(6)n+(30)/(6)-(1)/(6)\\\\A(n)=(n+29)/(3)\\\\\text{Put n = 1, n = 4 and n  = 10 to the formula:}\\\\A(1)=(1+29)/(3)=(30)/(3)=10\\\\A(4)=(4+29)/(3)=(33)/(3)=11\\\\A(10)=(10+29)/(3)=(39)/(3)=13`