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What is the force of friction between the dragsters tires and the track if the dragster mass is 300kg and the coefficient of the friction force is 0.8

2 Answers

2 votes

Final answer:

The force of friction between the dragster's tires and the track is 2352 newtons, calculated using the formula F=μN with the given mass of 300kg and the coefficient of friction 0.8.

Step-by-step explanation:

The force of friction between the dragster's tires and the track can be calculated using the formula F=μN, where F is the frictional force, μ is the coefficient of friction, and N is the normal force. In this case, the normal force is equal to the weight of the dragster, which is the mass (m) times the acceleration due to gravity (g), N = mg. Given that the mass (m) is 300kg and the coefficient of friction (μ) is 0.8, the force of friction can be calculated as:

F = μ × mg = 0.8 × 300kg × 9.8m/s² = 2352N

Therefore, the force of friction is 2352 newtons (N).

answered
User LowCool
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8.0k points
5 votes

Ff=μN=μmg=0.8*300*10=2400 N

answered
User Yuu Woods
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7.7k points