Register

Can you please solve this question with procedure, please???? . h (x) = 6x^2+ 3x + 1

Can you please solve this question with procedure, please???? . h (x) = 6x^2+ 3x + 1
asked 177k views
3 votes
Can you please solve this question with procedure, please????

. h (x) = 6x^2+ 3x + 1

asked
User Basanth
by
8.9k points

1 Answer

7 votes

Answer:


Explanation:

H


6x^2+3x+1=0\\a=6,b=3,c=1\\(-b+-√(b^2-4ac) )/2a\\\\(-3+-√(-15) )/(12) \\\\


The roots are:


(-3+-i√(15) )/(12)

answered
User Tim Cooley
by
7.8k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!