Question

((− 1/2 )y^4)^3·(–16y^2)

one half of y to the power of four to the power of three times sixteen y squared

Answer 1

2y^14

Explanation:

= (-1/2)^3 · (y^4)^3 · (-16) · y^2

= (-1/8)·(-16) · (y^(4·3) · y^2) . . . . . simplify some

= 2 · y^(12 +2) . . . . . simplify more

= 2y^14