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Only 29 and 31

Rewrite each expression eliminating fractions. Simplified answers may be left in terms of any of the six trigonometric functions.

100 points! Only 29 and 31 Rewrite each expression eliminating fractions. Simplified-example-1

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6 votes

Answer:

29. sec w csc w - sec^2 w

31. - tan ^2 k (sin k +1)

Explanation:

29. (cot w -1)/ (1- sin^2 w)

We know that cot w = cos w/ sin w

and 1 - sin^2 w = cos ^2 w

Replace these identities into the expression

(cos w/ sin w -1)

-----------------------

cos ^ 2 w

Get a common denominator on top of sin w

(cos w/ sin w -sin w/sin w)

-----------------------

cos ^ 2 w

(cos w - sinw)/ sin w

-----------------------

cos ^ 2 w

(cos w - sinw)

-----------------------

cos ^ 2 w sin w

Split into 2 terms

cos w sin w

----------------------- - ---------------------------------

cos ^ 2 w sin w cos ^2 w sin w


Cancel cos w in the first term and sin w in the second term

1 1

----------------------- - ---------------------------------

cos w sin w cos ^2 w

We know that 1/cos = sec and 1/ sin = csc

sec w csc w - sec^2 w



31. sin k/ (1 - csc k)

We know that csc k is 1/ sin k

sin k

---------------

1 - 1/ sin k

Get a common denominator for the bottom

sin k

---------------

sin k/ sin k - 1/ sin k

sin k

---------------

(sin k-1)/ sin k

Multiply by sin k/sin k

sin k * sin k

---------------

(sin k-1)/ sin k * sin k

sin k * sin k

---------------

(sin k-1)

sin^2 k

---------------

(sin k-1)

Multiply by (sin k +1)/ (sin k +1) so we can get rid of the denominator

sin^2 k (sin k +1)

-------------------------

(sin k-1) (sin k +1)

Foiling out the denominator, we get (sin^2 k-1)

sin^2 k (sin k +1)

-------------------------

(sin^2 k-1)

Factoring out a -1 from the denominator

sin^2 k (sin k +1)

-------------------------

-1 (1 - sin^2 k)

1 - sin ^2 k = cos ^ k

sin^2 k (sin k +1)

-------------------------

-1 (cos ^2 k)

sin ^2k/ cos ^2 k = tan ^2 k

- tan ^2 k (sin k +1)

answered
User Michael Rut
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