Question

F(x) ≥ -(x+4)^2
axis of symmetry:
vertex:

Answer 1

so the vertex is (-4, 0) and the axis of symmetry is x=-4

Explanation:

f(x) ≥ -(x+4)^2

f(x) ≥ -(x- -4)^2

this is in the form

f(x)> a(x-h)^2 +k

where (h,k) is the vertex and h is the axis of symmetry

so the vertex is (-4, 0) and the axis of symmetry is x=-4