Question

If f (x)=2x +6 and g (x) =x^3, what is ( g*f) (0)

Answer 1

(g*f)(0) is equal to 216.

Step-by-step explanation:

To find (g*f)(0), we need to first evaluate g(f(0)). Substitute 0 into the function f(x) = 2x + 6 to find f(0) = 2(0) + 6 = 6. Next, evaluate g(f(0)) by substituting 6 into the function g(x) = x^3. g(f(0)) = (f(0))^3 = 6^3 = 216. Therefore, (g*f)(0) = 216.

Answer 2

(g*f)(0)= (x^3)*(2x+6)
(g*f)(0)= (0^3)*(2(0)+6)
(g*f)(0)= (0)*(0+6)
(g*f)(0)= (0)*(6)
(g*f)(0)= 0