Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

Question

asked Mar 15, 2019 183k views

2 Answers

Pawneshwer Gupta · Answer 1 · 2019-03-19T22:30:19+0000

Answer:

Center (-2 , 4)

Explanation:

x^2 + 4x + y^2 - 8y = - 11

(x^2 + 4x + (4/2)^2 + (y^2 - 8y + (8/2)^2 ) = - 11 + 4 + 16

(x + 2)^2 + (y - 4)^2 = 9

Center (-2, 4)