Question

What is the pOH of a 7.9 x 10 ^-4 M OH- solution?

pOH= ?

Answer 1

pOH is defined as -log([OH-]).

pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1

Hope this helps!

Answer 2

Answer: pOH of the given hydroxide ion concentration is 3.10

Step-by-step explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:

`pOH=-\log[OH^-]`

We are given:

Hydroxide ion concentration,
`[OH^-]=7.9* 10^(-4)M`

Putting values in above equation, we get:

`pOH=-\log(7.9* 10^(-4))\\\\pOH=3.10`

Hence, pOH of the given hydroxide ion concentration is 3.10