Question

Identify the properties of the given quadratic y=-3x2+6x+17

A:

B:

C:



**Help, I’m confused**

Answer 1

A= -3

B= 6

C= 17

Axis of Symmetry: X=1

Vertex (1, 20)

The Vertex is at a: Maximum

Answer 2

A: Nature of root

we have a formula to find the roots of quadratic equation

`(-b\pm√(D))/(2a)`

where,
`D=b^2-4ac`

We have general form of quadratic equation as

`ax^2+bx+c`

Here, a=-3,b=6 and c=17 on substituting the values in
`D=b^2-4ac` and
`(b\pm√(D))/(2a)`

`D=6^2-4(-3)(17)=240`

Now, substitute D we get

`(-6\pm√(240))/(2(-3))=(3+2√(15))/(3),\frac{3-2sqrt{15}}{3}`

B: Open upward or downward

This given function is a downward parabola you can refer the figure in the attachment

C: End behaviour

Here, we have negative leading coefficient and even degree

Hence,

`x\rightarrow-\infty`
`f(x)\rightarrow-\infty`

`x\rightarrow\infty`
`f(x)\rightarrow-\infty`