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How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd

How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd
asked 156k views
3 votes
How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd

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User Orhan Yazar
by
8.6k points

1 Answer

4 votes

Use the formula of an area of a tringle:


A=(1)/(2)bc\sin A

We have b = 11 yd, c = 24 yd and m∠A = 67°


A=(1)/(2)(11)(24)\sin67^o


\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2

answered
User Curtis Rutland
by
8.5k points
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