6x-3y=3
-2x+6y=14
Elimination:
cancel out one of the variable to =0
(6x-3y=3)2
+
-2x+6y=14
________
12x-6y=6
+
-2x+6y=14
________
10x+0y=20
2. get X by itself
10x÷10= 1x. and 20÷10=2 so x=2
3. Now plug x=2 back into the second equation to find Y
-2(2)+6y=14
-4+6y=14
4. Get Y by itself
-4+6y=14
+4. -4
6y=10
÷6. ÷6
y=10/6 (simplify the fraction to: 5/2)
Your answers should be Y=5/3 and X=2
Just plug both of these numbers into each equation for the variable other represents to check your work.