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Solve (2a^x+1/2b^x)^2

asked
User Tom West
by
8.4k points

1 Answer

4 votes

Simplify 1/2b^x to b^x/2

(2a^x + b^x/2)^2

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2a^x)^2 + 2 × 2a^x × b^x/2 + (b^x/2)^2

Use the Multiplication Distributive Property: (xy)^a = x^a y^a

2^2(a^x)^2 + 2 ×2a^x × b^x/2 + (b^x/2)^2

Simplify 2^2 to 4

4(a^x) + 2 × 2a^x × b^x/2 + (b^x/2)^2

Use the Power Rule: (x^a)^b = x^ab

4a^x × 2 + 2 × 2a^x × b^x/2 + (b^x/2)^2

Regroup terms

4a^2x + 2 × 2a^x × b^x/2 + (b^x/2)^2

Use Division Distributive Property: (x/y)^a = x^a/y^a

4a^2x + 2 × 2a^x × b^x/2 + (b^x)^2/2^2

Use the Power Rule: (x^a)^b = x^ab

4a^2x + 2 × 2a^x × b^x/2 + b^x × 2/2^2

Regroup terms

4a^2x + 2 ×2a^x × b^x/2 + b^2x/2^2

Simplify 2^2 to 4

4a^2x + 2 × 2a^x × b^x/2 + b^2x/4

Simplify 2 × 2a^x × b^x/2 to 4a^xb^x/2

4a^2x + 4a^xb^x/2 + b^2x/4

Simplify 4a^xb^x/2 to 2a^xb^x

= 4a^2x + 2a^xb^x + b^2x/4

answered
User Kiryl
by
8.1k points

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