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Which of the following operations will change the solution of the system x − y = 2 and 3x − 3y = 2? multiply the first equation by 2 replace the first equation with the sum of x − y = 2 and 3x − 3y = 2 divide the second equation by 3 none of the above

2 Answers

5 votes

Answer:

D.

Explanation:

None of the above

got the right answer

answered
User Guicara
by
8.1k points
5 votes

Answer:

D) none of the above

Explanation:

Given system of equation is x − y = 2 and 3x − 3y = 2

And there are four choices

A) multiply the first equation by 2

B) replace the first equation with the sum of x − y = 2 and 3x − 3y = 2

C) divide the second equation by 3

D) none of the above


Now we need to find about which of the following operations will change the solution of the system x − y = 2 and 3x − 3y = 2?


We know that adding or subtracting or multiplying or dividing same thing on both sides of equation doesn't change the solution so A, C are not possible.

B) says to replace given equations by itself so that will also not change the solution

Hence correct choice will be D.


answered
User Ardget
by
9.0k points

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