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Write an equation for the transformed logarithm shown below, that passes through (-2,0) and (2,-2)

Write an equation for the transformed logarithm shown below, that passes through (-2,0) and-example-1

1 Answer

5 votes

The correct answer is:
f(x)=(-2log(x+3))/(log(5))

(In compact form:
f(x) = -2log_5(x+3)
)

Step-by-step explanation:

Follow these steps...

1. As it is a logarithmic graph, but reflected along x-axis, the general form of the function will be the following:

f(x) = -a*log(x) + k --- (A)

Where a represent the scale of the logarithmic graph, and k represents whether the graph is shifted down or up.

The negative sign indicates that the graph is reflected along the x-axis.

2. The vertical asymptote is at x = -3, the equation (A) will now become the following:

f(x) = -a*log(x + 3) + k --- (B)

The (x+3) part of the above equation shows that the graph is shifted 3 units towards left.

3. Now we need to find k and a. For finding k, plug in the point (-2,0) in equation (B):

0 = -a*log(-2+3) + k

0 = -a*0 + k

k = 0

4. For finding a, plug in the point (2,-2) and the value of k=0 in equation (B):

-2 = -a*log(2+3) + 0

a = 2/log(5)


Now plug in the values of a and k in equation (B), you will get the answer:

f(x) = -(2/log(5))*log(x+3) + 0


Therefore, the correct answer is:


f(x)=(-2log(x+3))/(log(5))

or, in compact form:


f(x) = -2log_5(x+3)


answered
User Kastriot Dreshaj
by
8.3k points

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