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Rewrite the following equation in the center-radius form of the equation of a circle. x2 - 6x + y2 - 6y + 17 = 0

Rewrite the following equation in the center-radius form of the equation of a circle. x2 - 6x + y2 - 6y + 17 = 0
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Rewrite the following equation in the center-radius form of the equation of a circle. x2 - 6x + y2 - 6y + 17 = 0

asked
User Kingtorus
by
8.4k points

1 Answer

1 vote

Answer:

The center of the circle is found at h,k

Center: (3,3)

These values represent the important values for graphing and analyzing a circle.

Center: (3,3)

Radius: 1




answered
User Jataro
by
8.4k points
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