Question

A researcher studying the nutritional value of a new candy places a 5.00-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.77 °C. If the heat capacity of the calorimeter is 47.10 kJ·K–1, how many nutritional Calories are there per gram of the candy?

Answer 1

Answer: 6236.48 cal/gram

Step-by-step explanation:
`Q= c* \Delta T`

Q= heat released

c = heat capacity of substance
`=47.10 kJK^(-1)=47100 JouleK^(-1)= 11.25kcalK^(-1)`

(1Joule=0.00024kCal) (1kcal=1000cal)

`\Delta T`=Change in temperature= 2.77C= 2.77K

`Q= 11257.17calK^(-1)* 2.77K`

`Q= 31182.4cal`

Now heat released per gram of the candy=
`(31182.4cal)/(5.00g)`

`=6236.48cal/gram`