Question

If 72 grams of water and 64 grams of oxygen are produced, what mass of h2o2 decomposed

Answer 1

H202 --> H20+02

x = 72 + 64

x = 136

Answer 2

Answer : The mass of
`H_2O_2` decomposed will be, 104 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

`2H_2O_2\rightarrow 2H_2O+O_2`

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of
`2H_2O_2` = Total mass of
`2H_2O+O_2`

As we are given :

Total mass of
`2H_2O+O_2` = 2(72) + 64 = 208 grams

So,

Total mass of
`2H_2O_2` = 208 grams

Total mass of
`H_2O_2` =
`(208)/(2)=104g`

Therefore, the mass of
`H_2O_2` decomposed will be, 104 grams