Question

Rewrite 0.37 in expanded form using powers of ten.

A) (3 × 1) + (7 × 10)
B) (3 × 10) + (7 × 100)
C) (3 ×
1
10
) + (7 ×
1
100
)
D) (3 ×
1
100
) + (7 ×
1
1000
)

Answer 1

`0.37=0.3+0.07=(3)/(10)+(7)/(100)=\left(3*(1)/(10)\right)+\left(7*(1)/(100)\right)\to\boxed{C.}`