Question

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

Enter your answer, as a decimal or whole number, in the boxes.

Answer 1

(-2,-1) and (1,0)

Explanation:

Answer 2

The endpoint coordinates for the mid-segment are:
`(-2,-1)` and
`(1,0)`

Explanation:

According to the given diagram, the coordinates of the vertices of
`\triangle BCD` are:
`B(-3,1), C(3,3)` and
`D(-1,-3)`

Now, the endpoints of the mid-segment of
`\triangle BCD` which is parallel to
`BC` will be the mid-points of sides
`BD` and
`CD`.

Formula for the coordinate of mid-point :
`((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2))`, where
`(x_(1), y_(1))` and
`(x_(2), y_(2))` are two endpoints.

So, the mid-point of
`BD` will be:
`((-3-1)/(2),(1-3)/(2))=((-4)/(2),(-2)/(2))=(-2,-1)`

and the mid-point of
`CD` will be:
`((3-1)/(2),(3-3)/(2))=((2)/(2),(0)/(2))=(1,0)`

Thus, the endpoint coordinates for the mid-segment of
`\triangle BCD` that is parallel to
`BC` are
`(-2,-1)` and
`(1,0)`