asked 41.2k views
4 votes
at a pizza shop, 75% of the customers order pizza, 20% of the customers order salad, and 15% of the customers order a pizza and a salad. If a customer is chosen at random, what is the probability that he or she orders either of pizza or salad?

asked
User Rafer
by
7.5k points

2 Answers

2 votes

Answer:

There would be a 65% chance of picking a customer who orders one or the other.

Explanation:

In order to find this, we first must find the percentage that orders only pizza. We can do this by subtracting the overlap from the total number.

75% - 15% = 60%

We need to do the same thing for salad.

20% - 15% = 5%

Now that we have the percentages who ordered just one or the other, we can add them together to get the total percentage who got either one or the other.

60% + 5% = 65%

answered
User Ahmad Sharif
by
8.1k points
7 votes

Answer:

It's actually 80%

Explanation:

answered
User OneRuler
by
7.5k points

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