What’s the vertex of f(x)=(x+5)^2

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asked Aug 13, 2019 101k views

1 Answer

Ian Richards · Answer 1 · 2019-08-20T01:48:31+0000

Answer: (-5, 0)

Step-by-step explanation: The equation is already in completing the square form, a(x-h)^2 + k so you have both the x and y values for the vertex. Since there is no k here, the y value is 0.

What’s the vertex of f(x)=(x+5)^2

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