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Which of the equation of the line with slope 3 that contains point (-1,5)

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The point-slope form:


y-y_1=m(x-x_1)

We have the slope m = 3 and the point (-1, 5). Substitute:


y-5=3(x-(-1))


\boxed{y-5=3(x+1)} use distributive property


y-5=3x+3 add 5 to both sides


\boxed{y=3x+8} - slope-intercept form

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User Schlebe
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