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What is the vertex of y=x^2+x-6

What is the vertex of y=x^2+x-6
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5 votes
What is the vertex of y=x^2+x-6

asked
User Sergej Christoforov
by
8.0k points

1 Answer

5 votes

Answer:


(-(1)/(2), -(25)/(4) )

Explanation:


y=a(x-h)^(2)+ k \\a= 1\\h=1/2\\k= -(25)/(4) \\


What is the vertex of y=x^2+x-6-example-1
answered
User Jimit Vaghela
by
7.9k points
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