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70 POINTS. Segment BK (K∈ AC ) is the angle bisector of ∠B in ΔABC. Point M is chosen on the side BC so that MK ≅ MB m∠MBK≅ m∠?

70 POINTS. Segment BK (K∈ AC ) is the angle bisector of ∠B in ΔABC. Point M is chosen on the side BC so that MK ≅ MB m∠MBK≅ m∠?
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5 votes
70 POINTS.

Segment BK (K∈ AC ) is the angle bisector of ∠B in ΔABC. Point M is chosen on the side BC so that MK ≅ MB

m∠MBK≅ m∠?

asked
User Boiler Bill
by
8.0k points

1 Answer

2 votes
MKB
because ΔBMK is an isosceles triangle
its base angle will be equal
answered
User Ssougnez
by
8.1k points
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