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How to simplify 2/√(2+√2)

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User Fetti
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1 Answer

3 votes


(2)/(√(2+\sqrt2))=(2)/(√(2+\sqrt2))\cdot(√(2-\sqrt2))/(√(2-\sqrt2))

use √(ab) = √a · √b


=(2√(2-\sqrt2))/(√((2+\sqrt2)(2-\sqrt2)))

use (a + b)(a - b) = a² - b²


=(2√(2-\sqrt2))/(√(2^2-(\sqrt2)^2))=(2√(2-\sqrt2))/(√(4-2))=(2√(2-\sqrt2))/(\sqrt2)\cdot(\sqrt2)/(\sqrt2)

use √a · √a = a and √(ab) = √a · √b


=(2√(2\cdot2-\sqrt2\cdot2))/(2)=√(4-2\sqrt2)\\\\Answer:\ \boxed{(2)/(√(2+\sqrt2))=√(4-2\sqrt2)}

answered
User Ford Guo
by
8.4k points

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