How many kj of heat are needed to completely vaporize 3.30 moles of h2o? the heat of vaporization for water at the boiling point is?

Question

asked Jan 24, 2019 89.0k views

1 Answer

Dinesh · Answer 1 · 2019-01-29T22:57:40+0000

The heat of vaporization for water at the boiling point is 40.6 kJ/mole

Q = ( moles of water ) ( molar latent enthalpy of water or heat of vaporization of water )

Q = 3.30 moles X 40.6 kJ/mole = 134 kJ