Question

Which of the answers are correct? there is possibly more than one.

Answer 1

`b_2 = (2A)/(h) -b_1`

Explanation:

Given

`A = (1)/(2)h(b_1 + b_2)`

Required

Select equivalent expressions

Multiply through by 2

`2*A = 2*(1)/(2)h(b_1 + b_2)`

`2*A = h(b_1 + b_2)`

`2A = h(b_1 + b_2)`

Divide through by h

`(2A)/(h) = (h(b_1 + b_2))/(h)`

`(2A)/(h) = b_1 + b_2`

Subtract b1 from both sides

`(2A)/(h) -b_1= -b_1 + b_1 + b_2`

`(2A)/(h) -b_1= b_2`

`b_2 = (2A)/(h) -b_1`

From the list of options, there is only one answer