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What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand …

What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand …
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What is the apparent weight of this same object at the neptune's equator? (note that neptune's "surface" is gaseous, not solid, so it is impossible to stand on it.)?

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User Cosmo D
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Since weight reflects the Normal Force of a surface to an object due to gravitational acceleration, if there is no physical surface to provide the Normal Force, the apparent weight would be 0N.
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User Alex Pacurar
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