Question

if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa

Answer 1

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂ Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂

p₁ = 485 kPa; V₁ = 648 mL

p₂ = ?; V₂ = 0.15 L = 150 mL Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa