Question

A television relay transmitter operates at a frequency of 927.9 MHz. Calculate the wavelength of the signal in nanometers. Is this visible light? (1 MHz = 1,000,000 Hz)

Answer 1

Answer : The wavelength of the signal is
`3.23* 10^8nm`. This is not a visible light.

Solution : Given,

Frequency = 927.9 MHz =
`927.9* 10^6Hz`
`(1MHz=10^6Hz)`

Speed of light =
`3* 10^8m/s`

Formula used :

`\\u=(c)/(\lambda)\\\lambda=(c)/(\\u)`

where,

`\\u` = frequency

`\lambda` = wavelength

c = speed of light

Now put all the given values in this formula, we get the wavelength of the signal.

`\lambda=(3* 10^8m/s)/(927.9* 10^6Hz)=0.323m=0.323* 10^9nm=3.23* 10^8nm`
`(1m=10^9nm)`

This is not a visible light because the range of visible light is (380 to 700 nm).

Therefore, the wavelength of the signal is
`3.23* 10^8nm`. This is not a visible light.